I understand the solution of . . . .

=sumproduct(--isnumber(match(a1:100,midwest,0)),b1:b100)

Now, I am going to throw one more issue into the problem.

What if I have a third column containing text (such as "revenues" and
"expense").

I need to add all the revenues for all the midwest departments into one
cell. Or, I need to add all the expenses for all the midwest departments
into one cell.




"Mike Moore" wrote in message
...
Is there a better array formula construction than the one described below?

I have two columns. Column A contains department designations (i.e. dept
A, dept B, dept C, dept D, etc). Column B contains dollar amounts.

The formula parameters are to sum multiple designated departments into one
cell.

I have the following formula developed:

{=sum((a1:a100=dept a)*(b1:b100))+sum((A1:a100=dept c)*(b1:b100))}

Instead of having two sum statements, can the formula be condensed to one
sum statement? For example,

{=sum((a1:a100=And(dept a, dept c))*(b1:b100))}

I have tried the above formula, but could not get it to work.

Second question - is it possible to set up the array formula to deal with
conditions that change? For example, department A and department C belong
to the Midwest region. However, next year department C belongs to the
Southwest region and department B belongs to the Midwest region.

I don't want to have to change hundreds of array formulas due to
department changes.

I have thought about using named ranges that designate a list of
departments belonging to regions. However, I have been unsuccessful in
this approach.