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Jon Peltier
 
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He he, I used a much less advanced technique than you did.

- Jon
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Jon Peltier, Microsoft Excel MVP
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Tushar Mehta wrote:

Hi Jon,

I cannot derive the formula you got but it cannot work for any vertical
or horizontal line.

For an approach from MathWorld see
http://mathworld.wolfram.com/Point-L...mensional.html

It gives the distance of (x0,y0) from ax+by+c=0 as
abs(a*x0+b*y0+c)/sqrt(a^2+b^2)



 
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