Check if first character of string is in array
That worked perfectly.
Thanks
Jonathan
"Tom Ogilvy" wrote in message
...
I would use:
Set cell = rng.Find(arrVar & "*", LookIn:=xlValues, _
Lookat:=xlWhole, MatchCase:=True)
Include a wildcard on the end of the search term. Look at xlWhole
This has worked for me in similar situations.
--
Regards,
Tom Ogilvy
"Jonathan" wrote in message
news:UwAhb.8713$XS4.7645@edtnps84...
You are correct, the output should be what you listed. For posting
purposes
I was planning on only putting one value in the array. Sorry about the
confusion.
Jonathan
"Tom Ogilvy" wrote in message
...
It should return
112 starts with 1
201 starts with 2
115 starts with 1
183 starts with 1
254 starts with 2
Maybe you should make it clearer what your criteria is.
Regards,
Tom Ogilvy
Jonathan wrote in message
news:Dskhb.1101$XS4.677@edtnps84...
Hello.
The code below works correctly except I need it to determine if a
string
begins with another string stored in an array, not contains the
string
stored in the array. For example
If the data is Should return Actually
Returns
112 112
112
201 115
201
115 183
115
183
183
254
390
here is the code that I have modified so far from another posting
here.
Dim rng As Range, cell As Range, arrVar As Variant
Dim strAddress1 As String, rngUnion As Range
Set rng = Range("Main!c:c")
For Each arrVar In Array("1", "2")
Set cell = rng.Find(arrVar, LookIn:=xlValues, Lookat:=xlPart,
MatchCase:=True)
If Not cell Is Nothing Then
strAddress1 = cell.Address
Do
If rngUnion Is Nothing Then
Set rngUnion = cell
Else
Set rngUnion = Union(cell, rngUnion)
End If
Set cell = rng.FindNext(cell)
Loop While Not cell Is Nothing And _
cell.Address < strAddress1
End If
Next arrVar
If Not rngUnion Is Nothing Then
rngUnion.EntireRow.Copy
End If
Any help would be appreciated.
Thanks
Jonathan
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