GetopenFilename default path
Hi,
Sub GetOpenFileNameExample()
Dim vFilename As Variant
Dim sPath As String
sPath = "c:\windows\temp\"
ChDrive sPath
ChDir sPath
vFilename = Application.GetOpenFilename("Microsoft
Excel Files (*.xls),*.xls", , "Please select the file(s)
to open", , False)
If TypeName(vFilename) = "Boolean" Then Exit Sub
If CStr(vFilename) = "" Then Exit Sub
If Dir(CStr(vFilename)) < "" Then
MsgBox "Exists!!!"
Else
' Now do something with vfilename, like:
' Workbook.Open Filename:=vFilename
End If
End Sub
Regards,
Jan Karel Pieterse
Excel TA/MVP
-----Original Message-----
Hello ,
I would like to know how i can give a Default Path (say
c:\xxxx\yyyy\zzzz)
when using GetopenFilename. Is this possible or is there
any other method to
do the same?
I'm using Excel 97
Regards,
SSR
.
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