Inputbox method using type:=8 - How to Cancel?
Thanks to everyone for helping me solve my problem.
Once I saw I could use "On Error" to overcome the error, I simplified on
Vasant's solution as follows:
+++++++++++++++++++++++++++++
Sub PickRow ( )
dim mynum
On Error Goto ErrorHandler
Set mynum= Application.InputBox ( "Select Row" , type: = 8 )
"some code"
ErrorHandler :
"some code" (or nothing if you just want to stop the procedure!)
End Sub
+++++++++++++++++++++++++++++
This is all I needed on this occasion.
Cheers
Joe
"Joe 90" wrote in message
...
Thanks Vasant
I'll give it a whirl today and report back
Joe
"Vasant Nanavati" wrote in message
...
Hi Joe:
You need something like the following awkward construction:
Sub ForceRangeInput()
Dim vResp As Variant
Do Until TypeName(vResp) = "Range"
On Error Resume Next
Set vResp = Application.InputBox("Test", Type:=8)
On Error GoTo 0
Loop
vResp.EntireRow.Select
End Sub
It's tricky only because the InputBox can return two types, an object
and
a
boolean.
Regards,
Vasant.
Regards,
Vasant.
"Joe 90" wrote in message
...
Hi,
I have an input box that asks the user to select a row (by picking a
cell).
The dialog box provides for an Ok button and a Cancel button.
If the user clicks the Cancel button I get an error in VBA.
I want to create a rounded app so everything works and
I have tried all ways to get this to go away but nothing I can do
will make the inputbox accept a "Range object" as the default, and
therefore
allow the Cancel. All I get is a "Run time error 13, type mismatch"
Here's the code:
+++++++++++++++++++++++++++++++++++++++++++
Sub PickRow ( )
dim mynum
set mynum = Application.InputBox ( "Select Row" , type: = 8 )
End Sub
+++++++++++++++++++++++++++++++++++++++++++
I have tried putting a variable for a range, a range address, and a
range
reference in as default e.g.
set mynum = Application.InputBox ( "Select Row" , , "$A$1" ,type: =
8 )
What am I doing wrong, or is this a vagary of the object model, that
because
I am choosing to seek a range object type, the Cancel button will
always
produce an error??
Hoping you can help..................................
Joe
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