Correction, this does work (in both formulae), and I have no idea why it
gave the div/0 error yesterday...
Oh well, onwards and (possibly) upwards.
"Steve Dunn" wrote in message
...
Can you show how one of our formulae can use INDEX instead of OFFSET in
this instance? I've tried:
$A$2:INDEX($A:$A,COUNTA($A:$A))
instead of:
OFFSET($A$2,,,COUNTA($A:$A)-1)
but the result is a div/0 error.
"T. Valko" wrote in message
...
Using named dynamic ranges will make the formula shorter and will be
easier to read and understand. And, if using INDEX to define those
ranges, the formula won't be volatile.
--
Biff
Microsoft Excel MVP
"Steve Dunn" wrote in message
...
Curious... why?
"T. Valko" wrote in message
...
Still suffers from the need for OFFSET() to
allow for increasing range lengths.
If they need dynamic ranges I would create those using
InsertNameDefine rather than building the range in the formula
itself: Also, I'd use INDEX rather than OFFSET if possible.
--
Biff
Microsoft Excel MVP
"Steve Dunn" wrote in message
...
Of course! Neater than mine, and (like mine) doesn't need to be array
entered. Still suffers from the need for OFFSET() to allow for
increasing range lengths.
Nice one.
"T. Valko" wrote in message
...
Ok, for alphnumerics try this array formula** :
=AVERAGE(IF(FREQUENCY(MATCH(A2:A10,A2:A10,0),ROW(A 2:A10)-ROW(A2)+1),B2:B10))
Assumes no empty cells in either range. Empty cells in the Invoice #
range will cause #N/A errors. Empty cells in the amount range could
cause an incorrect result depending on where the empty cells are
located.
** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and
the SHIFT key then hit ENTER.
--
Biff
Microsoft Excel MVP
"Nadine" wrote in message
...
You are correct. I should have thought of that. They are alpha
numeric
sometimes with a dash.
"T. Valko" wrote:
Here's a small sample file using your posted data that demonstrates
this.
zNadine.xls 14kb
http://cjoint.com/?eCdSeTo64Y
As you'll see the formula (which doesn't have to be array entered)
returns
the correct result.
If you're getting an error I suspect that your invoice #s aren't
really
numbers like your sample data, or they may look like numbers but
they're
really TEXT numbers. TEXT numbers and NUMERIC numbers are not the
same.
--
Biff
Microsoft Excel MVP
"Nadine" wrote in message
...
Didn't work. :( Result was #N/A as an array formula. Thanks
for trying.
"T. Valko" wrote:
Try this array formula** :
=AVERAGE(IF(FREQUENCY(A2:A9,A2:A9),B2:B9))
** array formulas need to be entered using the key combination
of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key
and the
SHIFT
key then hit ENTER.
--
Biff
Microsoft Excel MVP
"Nadine" wrote in message
...
I have a column of invoice numbers and multiple rows of data
pertaining
to
each one. So one invoice number could have 10 rows of data
pertaining
to
it
so the invoice number will be repeated 10 times. Then on each
line is
the
time it took to receive the data so this number will be the
same on all
10
lines. I have hundreds of rows of data but only a handful of
invoice
numbers. I need to find the average of the days based on the
unique
count
of
the invoice numbers. I already have my formula for the unique
count
but
now
need one for the average when the invoice numbers are not in
contiguous
cells
down the column.
Example:
Col A Col B
Invoice # # Days
12345 11
12345 11
12345 11
98995 15
66438 37
12345 11
98995 15
12345 11
So there are 3 unique invoice numbers. How do I write the
formula to
find
the average number days it took to receive all three? I'm in
Excel
2003.
.
.