counting identical items in a column and returning the occurre
In order to avoid the correction of each and every formula  in your private
case  I would suggest, in cell C1 to type the following formula and copy
down till C6:
=COUNTIF($A$1:$A$700,Row()1)
Micky
"ExcelWizardImNot" wrote:
That did it. Thanks much.
"Huber57" wrote:
Try this:
In C1 (to count the zeros)
=COUNTIF($A$1:$A$701,"0")
In C2 (to count the 1s):
=COUNTIF($A$1:$A$701,"1")
etc.
Hope that helps. If it does, rate it has helpful at the bottom of the post.
"ExcelWizardImNot" wrote:
I use excell 2000. I have one column with 700 rows. In each cell is one
number, either a 0, 1, 2, 3, 4, or 5. In the second column I have five rows,
each with one number in increasing order: 0, 1, 2, 3, 4, 5. Next to the
numbers 05 (in column three) I want the total number of occurances for each
number in column one. So out of the 700 rows, if the number 2 occurred 230
times, I want the number 230 to show in column 3 to correspond to the number
2 in column two. Any ideas?
