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March 27th 10, 10:09 AM posted to microsoft.public.excel.misc
 מיכאל (מיקי) אבידן external usenet poster First recorded activity by ExcelBanter: Dec 2009 Posts: 561
counting identical items in a column and returning the occurre

In order to avoid the correction of each and every formula - in your private
case - I would suggest, in cell C1 to type the following formula and copy
down till C6:
=COUNTIF(\$A\$1:\$A\$700,Row()-1)
Micky

"ExcelWizardImNot" wrote:

That did it. Thanks much.

"Huber57" wrote:

Try this:

In C1 (to count the zeros)

=COUNTIF(\$A\$1:\$A\$701,"0")

In C2 (to count the 1s):

=COUNTIF(\$A\$1:\$A\$701,"1")

etc.

Hope that helps. If it does, rate it has helpful at the bottom of the post.

"ExcelWizardImNot" wrote:

I use excell 2000. I have one column with 700 rows. In each cell is one
number, either a 0, 1, 2, 3, 4, or 5. In the second column I have five rows,
each with one number in increasing order: 0, 1, 2, 3, 4, 5. Next to the
numbers 0-5 (in column three) I want the total number of occurances for each
number in column one. So out of the 700 rows, if the number 2 occurred 230
times, I want the number 230 to show in column 3 to correspond to the number
2 in column two. Any ideas?