Counting the lack of a union of two lists
Hi,
Here's on Way to compare 2 lists. Lets assume your data are in columns A & B
starting in row 1. Put this in C1
=IF(B1="","",IF(ISNUMBER(MATCH(B1,A:A,0)),"",ROW() ))
Put this in D1
=IF(ISERROR(SMALL(C:C,ROW(A1))),"",INDEX(B:B,MATCH (SMALL(C:C,ROW(A1)),C:C,0)))
Now select C1 and d1 and drag down to the length of col B.
This gives a list of the differences in d1 down which you can now easily count
--
Mike
When competing hypotheses are otherwise equal, adopt the hypothesis that
introduces the fewest assumptions while still sufficiently answering the
question.
"Skippy Howenstein" wrote:
I'm trying to come up with a way to find the non-union of two lists. In
other words, I want to figure out error cases. I tried some COUNTIFS but I'm
just banging my head against the wall at 2:13AM. There must be a simple
solution.
Here's what I roughly have. I'm looking for cases where one of the values
in the Name column is NOT present in the Owner column. If all is well, every
owner will have a valid name. I'm looking for cases where that isn't true.
Name Owner Expected Result = 2 for Skippy and Scooby
Jim Jim
Joe Jim
Bob Bob
Sue Skippy
Sandy Joe
Sandy
Scooby
Sandy
Bob
Thanks in advance!
--
Just remember, wherever you go...there you are.
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