PERFECT!! That worked just how I needed it. I knew I needed an if plus the
concept from before but didn't know how to make it work. Thanks to everyone
for their input.

"Dave Peterson" wrote:

=if(count(a1:a7)=0,"No numbers",average(a1:a7))

Check for at least one number in that range first.

Erinayn wrote:

It is just an alpha N/A. Now that I'm looking at it only one person has
responded as such and the kicker is that no other responses for the area were
received so I'm getting an error since the average is of nothing.

Any thoughts on that?

"Dave Peterson" wrote:

If you really have N/A (plain old text) in that cell, then
=average(a1:a6)
should work fine.

=average() ignores non-numeric (but not errors) values.

On the other hand, if you have the error #N/A (resulting from a formula???) in
that range, then =average() will return an error.

You could use:
=SUMIF(A1:A6,"<1e37")/COUNT(A1:A6)

1E37 in scientific notation for a giant number. 1 followed by 37 zeros.



Erinayn wrote:

I have a 7 question survery with the following possible responses
1
2
3
4
5
N/A
We then take ther responses and average them. I'd like to eliminate the N/A
responses from the denominator and from the total sum. I currently have 1
cell for this operation - which doesn't work when the response is N/A since
it's a simple (sum)/7 equation.

Thanks for any help!

--

Dave Peterson
.


--

Dave Peterson
.