You're welcome. Thanks for the feedback!

--
Biff
Microsoft Excel MVP


"Frustrated by Averages"
wrote in message ...
That worked. Thanks!

"T. Valko" wrote:

Try this...

=IFERROR(SUM(B10,B22,B34)/INDEX(FREQUENCY((B10,B22,B34),0),2),"")

--
Biff
Microsoft Excel MVP


"Frustrated by Averages"
wrote in message
...
I am using 2007. There are no negative numbers. I would prefer that
the
cell be blank in place of the error code.

Thanks.

"T. Valko" wrote:

What version of Excel are you using?

Will there be any negative numbers in the cells?

What result do you want to replace the error?

--
Biff
Microsoft Excel MVP


"Frustrated by Averages"

wrote in message
...
Thanks again. One more question...Is there any easy way to hide a
"#DIV/0"
error? As the spreadsheet is populated it will go away, so this is
more
viewing purposes while the spreadsheet is blank.

"Jacob Skaria" wrote:

Try..
=SUM(B10,B22,B34)/SUM(COUNTIF(INDIRECT({"B10","B22","B34"}),"0"))

--
Jacob


"Frustrated by Averages" wrote:

I am attempting to average three separate cells (B10, B22 and
B34)
and
ignore
any zeros that exist. Each cell contains a formula that is
gathering
information from a pivot table. I need the average formula to
ignore
any
zeros that may be in these cells when calculating the average.

I have tried many different formulas, but nothing seems to work.
All
of the
solutions I have read related to this problem assume the cells
are
in a
continuous range (e.g. B10;B34).

Any help would be appreciated.


.



.