Hyperlink Formula Problem
try this ... sorry too long ...
=IF(B23="","",HYPERLINK("["&LEFT(CELL("filename"),SEARCH("[",CELL("filename"))-1)&MID(CELL("filename"),SEARCH("[",CELL("filename"))+1,
SEARCH("]",CELL("filename"))-SEARCH("[",CELL("filename"))-1)&"]"&ADDRESS(14,3,,,TEXT(ROW()-7,"0000")),TEXT(ROW()-7,"0000")))
HTH
--
MRT
"Keith Howie" wrote:
Hi,
I have a workbook with several worksheets. On my main sheet, in column a,
I have a list of numbers formatted to text 0001,0002,0003 etc. that are
generated automatically if the next column is populated. There are a
series of other sheets named 0001, 0002, 0003, etc. I want to create a
hyperlink to take the user to the corresponding sheet that is named the
same as the current cell on the listing sheet. I have created this
formula but it generates an error "Cannot open the specified file"
=IF(B23="","",HYPERLINK("file:///"&CELL("Filename")&" -
"&ADDRESS(14,3,,,TEXT(ROW()-7,"0000")),TEXT(ROW()-7,"0000")))
can anyone tell me what I am doing wrong?
Thanks
Keith
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