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Peo Sjoblom[_3_] Peo Sjoblom[_3_] is offline
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Default Average Function

Hi Linda,

First of all, June-08 is that supposed to be June 2008? If so make sure by
selecting a cell with this value and look in the formula bar and make sure
it doesn't say 6/8/2009, that is what my Excel does if I type June-08, Excel
thinks you mean June 8th current year. Anyway it is very easy to get average
for particular months and years,



=AVERAGE(IF((MONTH(A3:A21)=6)*(YEAR(A3:A21)=2008), B3:B21))



the above will average values in B where A = June 2008


but first make sure the dates are really June 08 values and not June 2009



--


Regards,


Peo Sjoblom


"Linda RQ" wrote in message
...
Hi Everyone,

I am using Excel 2003. I understand there is probably a very
sophisticated way to get what I want but I need to learn the simple way
first. I have a data sheet named "MICU". I inserted another sheet in the
workbook called "Stats". I want to break down the data by month on my new
Stats sheet. The MICU sheet has many columns of info. The 2 I think I
need to use is a column for start date "ThpyStDtTm" (Date and Time field
3/14/09 18:41) and a column called "VentLOSDays" (Number format with 2
decimal places).

Column A Column B
Month Ave VentLOS
June-08 2.41
July-08 3.75
Aug-08 3.42

I clicked on cell B2 (The June-08 Ave VentLOS cell) and inserted the ave
function using the Insert/Function tool menu then used the little function
arguments dialog box to go to the MICU sheet and selected all the numbers
in the average LOS column for patients started on therapy in June. Is
there a way to have an argument in there to find all the records from June
08 using the ThpyStDtTm column? This is what my function looks like so
far =AVERAGE ('MICU'!K17:K52). The July-08 looks like this =AVERAGE
('MICU'!K53:K93). This works great but I have to select by hand/eye which
is time consuming and errors occur if "I haven't had enough coffee" and I
am not sure what will happen if I decide to exclude a record later on, or
perhaps sort this list another way.

Thanks,
Linda