Not understanding COUNTIFS workaround in 2003
The "TRUE/FALSE" is input into the cell by a
checkbox elsewhere.
=SUMPRODUCT(--(A1:A100="high"),--(B1:B100="FALSE"))
If the cells are linked cells for the checkboxes then they return logical
TRUE/FALSE which are not text entries. Try removing the quotes from around
FALSE.
=SUMPRODUCT(--(A1:A100="high"),--(B1:B100=FALSE))
--
Biff
Microsoft Excel MVP
"Raymond W." wrote in message
...
Ah... I think I figured out the issue. The "TRUE/FALSE" is input into the
cell by a checkbox elsewhere. If I type "false" it works. if I use the
checkbox it does not. Is there a way around this?
"Fred Smith" wrote:
Sumproduct is the 2003 alternative to Countifs. Something like:
=sumproduct(--(a1:a100="high"),--(b1:b100))
Regards,
Fred.
"Raymond W." wrote in message
...
I have been reading up on how to work around the lack of a COUNTIFS
function
in 2003, but am apparently not doing something correctly.
I have a column with three possible answers (high, low, moderate) and a
column with two (True, False). I am wanting a total count of all rows
that
contain both "High" and "False". I either get #VALUE! errors, or counts
of
0
regardless of the data entered.
I am testing the code on '07, but will be running the sheet on '03. If
VBA
is the only way to accomplish this, I am fine using that, just need
some
pointers in the right direction.
Oddly enough it seems to work if I use something other than true or
false,
but that is the wording at my disposal...I feel as if I am beating my
head
against an invisible wall. If I cannot make it see TRUE or FALSE I
suppose
I
can use an IF statement elsewhere to change it to a 1 or 0 and use that
column instead... but that just seems like extra bloat.
Thanks in advance for the help
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