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Raymond W.[_2_] Raymond W.[_2_] is offline
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Default Not understanding COUNTIFS workaround in 2003

I have tried this. My result was always an answer of zero. Here is what I
used exactly:

=SUMPRODUCT(--(A1:A100="high"),--(B1:B100="FALSE"))


No matter how many rows I type in "high" on column A and then "FALSE" on
column B, the number never climbs. (A1 = high, and B1 = FALSE, result is
still 0). I even formatted the cell as text to make sure it wasn't
conflicting with an internal true/false operator. I tried in all capitals,
lowercase....

It works with anything other than true/false however

"Fred Smith" wrote:

Sumproduct is the 2003 alternative to Countifs. Something like:

=sumproduct(--(a1:a100="high"),--(b1:b100))

Regards,
Fred.

"Raymond W." wrote in message
...
I have been reading up on how to work around the lack of a COUNTIFS
function
in 2003, but am apparently not doing something correctly.

I have a column with three possible answers (high, low, moderate) and a
column with two (True, False). I am wanting a total count of all rows that
contain both "High" and "False". I either get #VALUE! errors, or counts of
0
regardless of the data entered.

I am testing the code on '07, but will be running the sheet on '03. If VBA
is the only way to accomplish this, I am fine using that, just need some
pointers in the right direction.

Oddly enough it seems to work if I use something other than true or false,
but that is the wording at my disposal...I feel as if I am beating my head
against an invisible wall. If I cannot make it see TRUE or FALSE I suppose
I
can use an IF statement elsewhere to change it to a 1 or 0 and use that
column instead... but that just seems like extra bloat.

Thanks in advance for the help