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Posted to microsoft.public.excel.worksheet.functions
Dave Peterson Dave Peterson is offline
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Default How to use ERROR.TYPE in an IF function?

I ususually weasel out and just check for an error:

=if(iserror(a1/b1),"",a1/b1)
or just check the denominator:
=if(b1=0,"",a1/b1)

But you could use a different formula to sum the column:

instead of:
=sum(a:a)

you can use:
=sumif(a:a,"<1e37")

1E37 is just a giant number (1 followed by 37 0's)



ramudo wrote:

I am getting error message #DIV/0! - How can I use ERROR.TYPE in an IF
function to bypass this error so that I can sum a column? OR, is there a
better way to achieve the same result? Thank you.


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Dave Peterson