Syntax error in nested IF statement.
It seems most likely that the value is some very small
non-zero number (though your assurance that it's
formatted as General makes that harder to believe).
To avoid the complications of the nested IFs, try entering
=F22=0 in a spare cell, and see if you get TRUE. If not,
try multiplying the value by large numbers to see what
you get - e.g, =F22*1000000
(I assume the value in I23 isn't zero, BTW...)
Andrew
On 15 July, 19:04, Sander wrote:
(Answered once, an hour ago; don't know why it has not appeared. *once
again...)
It is really zero, remains zero as decimal places are expanded, defined as
"0" by another IF statement, and formatted as General. *Thanks again for your
continued help.
"Jacob Skaria" wrote:
Check whether it is really zero; or displayed as zero
=IF(J22<0,1000,IF(INT(J22)=0,I23,0))
If this post helps click Yes
---------------
Jacob Skaria
"Sander" wrote:
For I22: *=IF(J22<0,1000,IF(J220,0,I23)).
This works when J22 or < 0, but not when J22=0, when it should take I23.
Why is that? *Thank you.
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