Thanks, this is both useful and elegant. I had some trouble at first because
I had the formula in column L (so ti produced a circular) but that was an
easy fix. Thanks again!

"T. Valko" wrote:

While we're at it, this can be done without the use of volatile functions:

=SLOPE(INDEX(L:L,ROW()):INDEX(L:L,B9),INDEX(A:A,RO W()):INDEX(A:A,B9))

--
Biff
Microsoft Excel MVP


"T. Valko" wrote in message
...
The ROW() function collapses the array to a single cell.

Then why does this work:

=SUM(INDIRECT("$L"&TEXT(ROW(),0)&":$L$"&TEXT($B$9, 0)),INDIRECT("$A"&TEXT(ROW(),0)&":$A$"&TEXT($B$9,0 )))

You solution will work but your reasoning is backwards. The ROW function
*always* returns an array even if the reference is to a single element. So
ROW is taking the single cell ref and making it an array. What's happening
seems to be function specific. SLOPE maintains the ROW reference as an
array but other functions, like SUM, will "convert" the array to a
non-array single element.

Here's another way:

=SLOPE(INDIRECT("L"&INDEX(ROW(),1)&":L"&B9),INDIRE CT("A"&INDEX(ROW(),1)&":A"&B9))

--
Biff
Microsoft Excel MVP


"Shane Devenshire" wrote in
message ...
Hi,

The ROW() function collapses the array to a single cell. To get around
this try

=SLOPE(INDIRECT("A"&CELL("row")&":A"&B9),INDIRECT( "L"&CELL("row")&":L"&B9))

--
If this helps, please click the Yes button.

Cheers,
Shane Devenshire


"Nick H" wrote:

I have two columns of numbers, and I want to calculate the slope of the
regression line for the data from the current row to the bottom of the
table.
I built this formula:

=SLOPE(INDIRECT("$L"&TEXT(ROW(),0)&":$L$"&TEXT($B$ 9,0)),INDIRECT("$A"&TEXT(ROW(),0)&":$A$"&TEXT($B$9 ,0)))

The y values are in column L, the x values in column A, and the row
number
of the bottom of the table is in cell B9.

I'm getting #NUM; when I step through the error analysis, it seems like
I'm
getting valid ranges. Can anyone help me with this? Thanks.