Two reasons:

*FIRST*
Your formula is wrong!
It's returning "1A".

You should use:

=MID(M3,8,1)
OR
=Right(Left(M3,8))

*SECOND*

Text functions return TEXT, *not* true numbers.

=Right(Left(M3,8))
AND
=MID(M3,8,1)

Will return "1" *not* 1.

So, you *either* make the text formula return a true number:

=--Right(Left(M3,8))
=IF(--Right(Left(M3,8))=1,"1/8 NPT","1/4 NPT")
AND
=--MID(M3,8,1)
=IF(--MID(M3,8,1)=1,"1/8 NPT","1/4 NPT")

OR

You revise your IF() formula to look for a TEXT "1":

=IF(MID(M3,8,1)="1","1/8 NPT","1/4 NPT")
=IF(Right(Left(M3,8))="1","1/8 NPT","1/4 NPT")
--

HTH,

RD
================================================== ===
Please keep all correspondence within the Group, so all may benefit!
================================================== ===


"Charlie" wrote in message
...
Now that I am able to pull the value of the character out of the string. I
need to use an IF statement to have TRUE/FALSE text returned.

=IF(MID(M3,8,2)=1,"1/8 NPT","1/4 NPT") This returns a False value, would you
know why?
M3 = AP10-FG1A1P

"Mike H" wrote:

try this

=MID(A1,8,1)

Mike

"Charlie" wrote:

I need a function that will pull a character value from a specified cell
and
string location so I can put it into an if statement to return a text
string.

i.e.
Say I have this text string, AP10-FG1A1P, and I wanted to pull the value
of
the 8th character. What do I use?

Find and Search are not returning the value, but only the position.
Right and Left return too many characters. Although they are good for
the
first and last character value when needed.