When the OP asked for "percent of increase", I assumed that he was asking
not for the slope =(Y2-Y1)/(X2-X1) but for the increase as a percentage of
the original value =(Y2-Y1)/Y1. In each case, of course, the answer would
need to be expressed as a percentage. My interpretation may be supported by
the fact that the OP said he was expecting about 2%, whereas Shane's formula
gives 219.73%.
--
David Biddulph
Shane Devenshire wrote:
Hi,
Since this is a linear equation, the delta Y/delta X is the same
regardless of the x position. Here is the basic idea
=(Y2-Y1)/(X2-X1)
Since you can use any values I chose 1 and 2 as my X positions and
substituted in you other numbers:
=((2.1973*2+3211.1)-(2.1973*1+3211.1))/(2-1)
the answer is 2.1973
However, as Bernard said an R squared value of 0.0046 basically means
the trend line Excel found does not match the data at all. Most
likely this is because the data is not linear, so you should test the
other types of trendlines.
The percentage increase in Y depends on your X values.
=2.1973*(X_new-X_old)/(2.1973*X_old + 3211.2) and format as
percentage. --
David Biddulph
rml wrote:
It should be a small increase of say 2% or so. Anyways, how would I
convert those equations to a percent?
Thanks.
"Bernard Liengme" wrote:
With an Rē value that low, I would not trust any derived data.
best wishes
--
Bernard V Liengme
Microsoft Excel MVP
http://people.stfx.ca/bliengme
remove caps from email
"rml" wrote in message
...
I created a chart with a trendline. How can I figure out the
percent of increase from the formula generated from trendline?
y = 2.1973x + 3211.2
Rē = 0.0046
Thanks!