Hi,

Since this is a linear equation, the delta Y/delta X is the same regardless
of the x position. Here is the basic idea

=(Y2-Y1)/(X2-X1)

Since you can use any values I chose 1 and 2 as my X positions and
substituted in you other numbers:

=((2.1973*2+3211.1)-(2.1973*1+3211.1))/(2-1)

the answer is 2.1973

However, as Bernard said an R squared value of 0.0046 basically means the
trend line Excel found does not match the data at all. Most likely this is
because the data is not linear, so you should test the other types of
trendlines.

--
If this helps, please click the Yes button.

Cheers,
Shane Devenshire


"David Biddulph" wrote:

The percentage increase in Y depends on your X values.
=2.1973*(X_new-X_old)/(2.1973*X_old + 3211.2) and format as percentage.
--
David Biddulph

rml wrote:
It should be a small increase of say 2% or so. Anyways, how would I
convert those equations to a percent?

Thanks.

"Bernard Liengme" wrote:

With an R² value that low, I would not trust any derived data.
best wishes
--
Bernard V Liengme
Microsoft Excel MVP
http://people.stfx.ca/bliengme
remove caps from email

"rml" wrote in message
...
I created a chart with a trendline. How can I figure out the
percent of increase from the formula generated from trendline?

y = 2.1973x + 3211.2
R² = 0.0046

Thanks!