As =LEN('Q2'!E8)=26 returned FALSE, that confirms (as I suggested earlier)
that the content of your cell is not "completed, carried forward", because
if you copy the string "completed, carried forward" [without the quotes]
into the cell and use the LEN function on that you will see that it IS 26
characters.
What does =LEN('Q2'!E8) return? How many characters are in the cell, if it
isn't 26?
What does =CODE(RIGHT(A8)) return? It will be 100 if the last character in
the cell is "d". It will be 32 if the last character is a space, and 160
if it is a non-breaking space.
--
David Biddulph

Richard Horn wrote:
Yes David, that's affirmative. I am certainily stuck.

I tried your 3 suggestions:
1. =('Q2'!E8<"completed, carried forward") which returned all TRUE
even though column does contain a Completed status.
2. =('Q2'!E8="completed, carried forward") which returned all FALSE
even though column does contain a Completed status.
3. =LEN('Q2'!E8)=26 which returned all FALSE even though column does
contain a Completed status.

Each of your suggested helpers I pasted in a cell, then copied them
down to cover a range of cells I wanted to test query.

Not unless I am totally misunderstanding what your trying to help me
with, I am not sure how to make this work, but I certainly appreciate
your patience is trying to share your experience.

thanks Richard

"David Biddulph" wrote:

So you've confirmed that you have a problem, and that your formula
doesn't match your data, but you've not bothered with my other
suggestions? --
David Biddulph

Richard Horn wrote:
With the helper column I copied down, it did not return as it
should:

Whether I used =('Q2'!E8<"completed, carried forward") which
returned all TRUE even though column does contain a Completed
status.

or

=('Q2'!E8="completed, carried forward") which returned all FALSE
even though column does contain a Completed status.

For column E on my Q2 worksheet I am using a Validation, List, from
the bottom of my sheet, so the project lead can have a drop-down box
to select their current status. So there would not be any abnormal
characters or spaces when I am trying to comprise my formula.

"David Biddulph" wrote:

That probably means that you've got some slight difference in the
content of column E, perhaps spare spaces or other characters (such
as non-breaking spaces) in the cell.

You can check with a helper column:
=('Q2'!E8<"completed, carried forward") and copy down
and/or
=('Q2'!E8="completed, carried forward") and copy down.

You might also want to try =LEN('Q2'!E8)=26

You might wish to copy the string (which you think is ="completed,
carried forward") from a suitable cell in column E into your
formula. --
David Biddulph

"Richard Horn" <Richard wrote in
message ...
I found these comments very helpful so far. Now I am stumped.

I have a workbook with multiple worksheets and I am making a
summary page up
front for management review.

Here's what I am trying to do. From worksheet named Q2, I have all
my projects leads in column D, and then the current status of
their projects in
column E, for instance, intake, editing, pending, etc.. What I am
trying to
do is count all the instances of one project lead, in this case
chris craig,
and then I want to know all projects she is working on, unless, or
except, if
the status is completed or carried forward. If the status for a
project lead
is completed or carried, then do not count.

This is the formula I am trying to use, but is is counting all
projects for
the given lead with all statuses, including completed and carried
forward.

=SUMPRODUCT(('Q2'!D8:D33="chris craig")*('Q2'!E8:E33<"completed,
carried forward"))

"T. Valko" wrote:

You're welcome. Thanks for the feedback!

--
Biff
Microsoft Excel MVP


"Steve Scatt" wrote in
message
...
Thanks Biff,

tried it again and made sure no unseen characters and it seems
to work. Cheers.

"Steve Scatt" wrote:

I have 2 separate columns and I am trying to count the nu,ber
of occurances
for a 2 different values. i.e. how many times admin column C
and sick Column
D show up. Tried the SUMPRODUCT and it doesn't seem to work. I
get a value of
0 when there should be 3.

"David Biddulph" wrote:

=SUMPRODUCT((A1:A100="A")*(A1:A100<="D")*(B1:B100 ="psychiatrist"))
--
David Biddulph

"Nick Brunetti" wrote
in message
...
I am trying to count a cell if criteria from two separate
columns are
met.

For example, my first column has the letters A, B, C, D or no
letters
at
all. The second column has different descriptive words (i.e.
internal
medicine, psychiatrist, etc). I would like a cell to be
counted if a
cell
in
the first column contains an A or B or C or D AND a cell in
the second
colum
contains the word "psychiatrist".

What is the best function/formula to use for this problem?

"Bob Phillips" wrote:

=COUNTIF(A1:A100,"*@*")

--
---
HTH

Bob

(there's no email, no snail mail, but somewhere should be
gmail in
my
addy)



"Joan NYC" wrote in
message
...
Aha... Sumproduct is not a function I ever tried

I have a column of text. Some cells contain the character
"@" with a
space
preceding the rest of text in the cell. I realize the @
could be
considered
an operator so it is preceded with an apostrophe to
designate text. I
want
to sum the cells that have the "@"

Thanks

"David Biddulph" wrote:

You'll need to be a bit clearer as to what you're trying
to do.
If
COUNTIF
or SUMIF doesn't do the job, you may want to try
SUMPRODUCT. --
David Biddulph

"Joan NYC" wrote in
message
...
I have been trying to calculate a column of Text in order
to sum
contents
by
certain criteria

I have tried Count, CoutA and CountIF and cannot be able
to get
anything
to
work.

Am I barking up the wrong tree? :) Can this be done?

Thanks much.