Excel 2003 Calculation Problems
I missed answering the question
=ROUND(MOD(F17-F18,F21),1)
Mike
"Mike H" wrote:
How do I fix it?
You don't it's not broken
The modulus is what's left over after division so
=MOD(F17-F18,F21)
should return zero compared to
=(F17-F18)/F21 which returns 5
The formula
=MOD(F17-F18,F21) if set to lots of decimal places returns
-0.0000000000000568434
which is near as dammit zero with the diference being caused by excel
conversions between binary and decimal where often there is no precise binary
representation of a number.
Mike
"ak_edm" wrote:
I have Excel 2003 (11.8237.8221) SP3 according to the ABOUT screen in the
HELP menu. The three numbers and their cell locations a
F17 = 1887.36
F18 = 314.56
F21 = 314.56
Note that 314.56 x 6 = 1887.36, so why is this happening?
The formula =(1887.36-314.56)/314.56 equals 5
but the formula =MOD(1887.36-314.56,314.56) equals -5.68434E-14
(for this next one I formatted the digits in the Excel cell as far as I
thought good)
The formula =(F17-F18)/F21 equals 5.000000000000000
but the formula =MOD(F17-F18,F21) equals 0.000000000000171
Why?
How do I fix it?
- Eric
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