sorry - forgot the brackets

=MID(A1,FIND("(",A1),LEN(A1)-FIND("(",A1)+1) for numbers

is correct


On 17 Sty, 12:27, Jarek Kujawa wrote:
one method:

=LEFT(A1,FIND("(",A1)-1) for names
=MID(A1,FIND("(",A1)+1,LEN(A1)-FIND("(",A1)-1) for numbers

should you need the numbers to be "numeric" not text then
=MID(A1,FIND("(",A1)+1,LEN(A1)-FIND("(",A1)-1)*1

HIH

On 17 Sty, 12:05, "Stan in South Africa" <me@there wrote:



Using Vista, Excel 2007

I have the following:
In A1 - 'Bill Smith (2468)'
In A2 - 'James Sinclair (659873)'
and so on to A350, with names of various lengths and numbers containing a
different number of digits in parenthesis.

I require, in text format:
In B1 - 'Bill Smith' *In C1 '(2468)'
In B2 - 'James Sinclair' In C2 '(659873)'
and so on to row 350.

Any advice will be appreciated.- Ukryj cytowany tekst -

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