You sound organized in your development procedures.
Not as haphazard as us folks who dye for a living, and just use this stuff
to get *OUR* job done.<bg
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Regards,
RD
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"Peo Sjoblom" wrote in message
...
When I test a formula I usually put the values in a range, i.e.
A B
H 1
HP 0.5
then I use the range itself in the formula and finally I select the range in
the formula
bar and press F9 to hardcode it. Since most data are in rows in a column I
usually use that unless the OP notes in his/her post using data going
across,
then it would be comma instead when I hard code my formula test
Regards,
Peo Sjoblom
"RagDyer" wrote:
Topic of conversation:
What made you use semicolons in the array constant?
Usually they separate rows, as opposed to columns.
It seems Countif() accepts either [ , ] or [ ; ],
As does an "OR",
=IF(OR(A1={"P";"HP"}),"OK","NG")
While regular
=SUMPRODUCT((A1:A100={"P","HP"})*{1,0.5})
Does not!
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Regards,
RD
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"Peo Sjoblom" wrote in message
...
True, although it will not work in this scenario
=SUMPRODUCT(--(A1:H100={"P","HP"})*({1,0.5}))
will return error while this will work
=SUMPRODUCT(COUNTIF(A1:H100,{"P";"HP"}),{1;0.5})
so it is a bit more robust
I believe I picked up this formula from Daniel M
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Regards,
Peo Sjoblom
(No private emails please, for everyone's
benefit keep the discussion in the newsgroup/forum)
"RagDyer" wrote in message
...
How about this way Peo, without the additional function:
=SUMPRODUCT(--(A1:A100={"P","HP"})*({1,0.5}))
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Regards,
RD
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"Peo Sjoblom" wrote in message
...
One way
=SUMPRODUCT(COUNTIF(A1:A100,{"P";"HP"}),{1;0.5})
where your P/HP days are in A1:A100
Regards,
Peo Sjoblom
"ryanjh79" wrote:
I would like to use the countif function to count a letter a a half
".5"
instead of as a whole "1." The application that it would be used for is
on
a
payroll workbook. i.e. "P" would eaqul a whole personal day whereas a
"HP"
would be a half of a personal day. From there I would like to add all
of
the
"P's" and "HP's" in one Cell. this would be like 4.5 days used compared
with
4 days used (P,P,P,P, HP)=4.5
Thanks,
Brandon
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