Do you need the double unary minus operators, Per? Doesn't the plus
operation coerce the conversion from boolean to number?
Wouldn't =(OR(C6="Y",D6="Y"))+(OR(F6="Y",G6="Y")) do the job?
--
David Biddulph

"Per Jessen" wrote in message
...
Hi

Look at this example:

=--(OR(C6="Y",D6="Y"))+--(OR(F6="Y",G6="Y"))

Hopes it helps.

Regards,
Per

On 2 Dec., 20:27, Navy Luke <Navy
wrote:
I have either a Y or N in cells based on two different things that
happened
for the day (which explains why there are 7 COUNTIF statements, they all
pertain to a single day of the week).

What I am trying to do is to add up the number of days that EITHER one or
the other happened. I used the formula below:

=COUNTIF(C6:D6,"Y")+COUNTIF(F6:G6,"Y")+COUNTIF(I6: J6,"Y")+COUNTIF(L6:M6,"Y"*)+COUNTIF(O6:P6,"Y")+COU NTIF(R6:S6,"Y")+COUNTIF(U6:V6,"Y")&"
/ 7"

However, seeing as how I got a result of 8 / 7 for some days (in which on
a
single day BOTH things happened), I realized the problem with the
function,
as it is simply counting "Y's". I need to be able to count whether there's
a
Y in EITHER one in the range (which pertains to a single day).

I tried to solve this with corresponding statements of -COUNTIF(C6, $D$6)
(etc), but for those in which there were NO Y's for the week, it returned
a
negative number because it subtracted the fact that the N's are the same.

I'm stumped. Any help would be greatly appreciated, as I have 150 rows
each
on 3 different sheets and manually adding up all these would take me a
long
time (also, I plan to use this a great deal in the future, so it benefits
me
for a great deal of time), so I'm hoping to get a response in the next
couple
hours that will help me.

Thank you.