The MIN(IF is broken

=MIN(IF(J11:J40="b",D11:D40,"")) is the correct array part.
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Gary''s Student - gsnu200813


"Rene" wrote:

=MIN(MIN(J11:J40,"b",D11:D40),MIN('[abc.xlsx]2008 mine'!G313:G367))
{=MIN(MIN(if(J11:J40,"b",D11:D40),MIN('[abc.xlsx]2008 mine'!G313:G367)))}

both return a value error

"Gary''s Student" wrote:

Encompase the two equations like:

=MIN(MIN(),MIN())
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Gary''s Student - gsnu200813


"Rene" wrote:

Hello again. I've tried and tried to combine the two formulas to find the MIN
(one number)...help.

{=MIN(IF(J11:J40="b",D11:D40))}
=MIN('[abc.xlsx]2008 Mine'!G313:G367)

Also, same formula using AVERAGE in place of MIN

Thank you