Topic of conversation:

What made you use semicolons in the array constant?
Usually they separate rows, as opposed to columns.
It seems Countif() accepts either [ , ] or [ ; ],
As does an "OR",
=IF(OR(A1={"P";"HP"}),"OK","NG")
While regular
=SUMPRODUCT((A1:A100={"P","HP"})*{1,0.5})
Does not!
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Regards,

RD
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"Peo Sjoblom" wrote in message
...
True, although it will not work in this scenario

=SUMPRODUCT(--(A1:H100={"P","HP"})*({1,0.5}))

will return error while this will work

=SUMPRODUCT(COUNTIF(A1:H100,{"P";"HP"}),{1;0.5})

so it is a bit more robust

I believe I picked up this formula from Daniel M

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Regards,

Peo Sjoblom

(No private emails please, for everyone's
benefit keep the discussion in the newsgroup/forum)



"RagDyer" wrote in message
...
How about this way Peo, without the additional function:

=SUMPRODUCT(--(A1:A100={"P","HP"})*({1,0.5}))
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Regards,

RD
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Please keep all correspondence within the Group, so all may benefit!
-------------------------------------------------------------------


"Peo Sjoblom" wrote in message
...
One way

=SUMPRODUCT(COUNTIF(A1:A100,{"P";"HP"}),{1;0.5})

where your P/HP days are in A1:A100


Regards,

Peo Sjoblom



"ryanjh79" wrote:

I would like to use the countif function to count a letter a a half ".5"
instead of as a whole "1." The application that it would be used for is
on
a
payroll workbook. i.e. "P" would eaqul a whole personal day whereas a
"HP"
would be a half of a personal day. From there I would like to add all of
the
"P's" and "HP's" in one Cell. this would be like 4.5 days used compared
with
4 days used (P,P,P,P, HP)=4.5
Thanks,

Brandon