Thank u Mike ,

You have taken many efforts and really that works.The formula which you
have modified working very well and gives me precision up to 6 microns which
is acceptable to be.
Thanks Once again
H S Shastri

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"Mike H" wrote:

This is now bugging me. The interval between (11) 8.8154 & (12) 8.7089 =
-0.01065 and can be shown thus:-