That's odd. Both functions kept the leading zeros for me. (xl2003)
That's when I called it from a worksheet cell:
=reverse(a1)
or
=reverse2(a1)
But if I called it from a sub and populated another cell, I lost the leading
0's.
Sub testme()
Range("B1").Value = Reverse(Range("a1"))
End Sub
But you could do this:
Sub testme2()
Range("B1").Value = "'" & Reverse(Range("a1"))
End Sub
or even:
Sub testme3()
With Range("B1")
.NumberFormat = "@"
.Value = Reverse(Range("a1"))
End With
End Sub
ac512 wrote:
this works perfectly, except for the fact that if a number ends in one or
more zeros, the zeros are dropped off
"Andy Brown" wrote:
"ac512" wrote in message
...
how do I reverse the values of a cell (eg. 1234 becomes 4321)???
Try this UDF (from John Walkenbach's site) in a plain VBA module:
Function Reverse(InString) As String
'UDF to reverse string - John W
Dim i As Integer
Dim StringLength As Integer
Reverse = ""
StringLength = Len(InString)
For i = StringLength To 1 Step -1
Reverse = Reverse & Mid(InString, i, 1)
Next i
End Function
HTH,
Andy
--
Dave Peterson
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