Summation Operator
y=2i+1 when i=1 initially with a final value of 10.
y=(2x1+1)+(2x2+1)+...+(2x10+1)
Hi. For this first question...
n=10
? n + n*(1 + n)
120
For Second question:
Chg= 0.000001
? (Sqr(Chg^2 + Chg) - Chg)/Chg
999.000499999875
Hence, 999 is the last value.
1,000 will put you over.
and I need to find the approximate answer for y when the addition of the
successive terms causes a less than 0.0001% change in y
n=999
? n/(1 + n)
0.999
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HTH :)
Dana DeLouis
"Sapphy" wrote in message ...
Hi,
I'm trying to work out a way of getting Excel 2003 to answer
y=2i+1 when i=1 initially with a final value of 10.
y=(2x1+1)+(2x2+1)+...+(2x10+1)
I could type it by hand however my next question requires the upper limit n
to be infinity for the eqn
y=1/i(i-1) when i=1 initially and the final value for i=infinity
y=(1/(1(1+1))+(1/2(2+1)+...(1/infinity(infinity+1)
and I eed to find the approximate answer for y when the addition of the
successive terms causes a lass than 0.0001% change in y, as well as the last
value for i when the program stops.
Am utterly stumped! Please help,
Thank you.
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