You're welcome. Thanks for the feedback!

--
Biff
Microsoft Excel MVP


"Steve Scatt" wrote in message
...
Thanks Biff,

tried it again and made sure no unseen characters and it seems to work.
Cheers.

"Steve Scatt" wrote:

I have 2 separate columns and I am trying to count the nu,ber of
occurances
for a 2 different values. i.e. how many times admin column C and sick
Column
D show up. Tried the SUMPRODUCT and it doesn't seem to work. I get a
value of
0 when there should be 3.

"David Biddulph" wrote:

=SUMPRODUCT((A1:A100="A")*(A1:A100<="D")*(B1:B100 ="psychiatrist"))
--
David Biddulph

"Nick Brunetti" wrote in
message
...
I am trying to count a cell if criteria from two separate columns are
met.

For example, my first column has the letters A, B, C, D or no letters
at
all. The second column has different descriptive words (i.e.
internal
medicine, psychiatrist, etc). I would like a cell to be counted if a
cell
in
the first column contains an A or B or C or D AND a cell in the
second
colum
contains the word "psychiatrist".

What is the best function/formula to use for this problem?

"Bob Phillips" wrote:

=COUNTIF(A1:A100,"*@*")

--
---
HTH

Bob

(there's no email, no snail mail, but somewhere should be gmail in
my
addy)



"Joan NYC" wrote in message
...
Aha... Sumproduct is not a function I ever tried

I have a column of text. Some cells contain the character "@"
with a
space
preceding the rest of text in the cell. I realize the @ could be
considered
an operator so it is preceded with an apostrophe to designate
text. I
want
to sum the cells that have the "@"

Thanks

"David Biddulph" wrote:

You'll need to be a bit clearer as to what you're trying to do.
If
COUNTIF
or SUMIF doesn't do the job, you may want to try SUMPRODUCT.
--
David Biddulph

"Joan NYC" wrote in message
...
I have been trying to calculate a column of Text in order to sum
contents
by
certain criteria

I have tried Count, CoutA and CountIF and cannot be able to get
anything
to
work.

Am I barking up the wrong tree? :) Can this be done?

Thanks much.