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Rick Rothstein \(MVP - VB\)[_966_] Rick Rothstein \(MVP - VB\)[_966_] is offline
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Default User Defined FUNCTION

The OP mentioned he wanted this only if the number is 8 digits long as well.
True, his examples all show 8-digit numbers, but I made the same kind of
assumption in another thread yesterday and my assumption turned out to be
wrong. So, just in case...

=IF(AND(RIGHT(A1,4)="0000",LEN(A1)=8),A1/10000,A1)

Rick


"Jim Thomlinson" wrote in message
...
As opposed to a udf how about this...

=IF(RIGHT(A1, 4) = "0000", A1/10000, A1)
--
HTH...

Jim Thomlinson


"EAK" wrote:

I need a User Defined Function that check if a number or string is 8
digits
long and ends in "0000". If it meets the two creteria, then it should
drop
those the "0000" and return only the remaining 4 numbers for example,

23000016 result 23000016
23160000 result 2316
19000000 result 1900

FYI using Substitute() gives me the wrong result sometimes.

FUNCTION Truc(location)

END Function