Caveat - don't try to use years before 1901.

Pete

On Jun 30, 11:00*am, "Rick Rothstein \(MVP - VB\)"
wrote:
And, generalizing this, here is the formula that returns TRUE if a given
year is a leap year...

=ISNUMBER(--(A1&"-02-29"))

where A1 contains a year value (2000, 2007, 2008, etc.). If A1 contains a
date, then that date is in a leap year if this formula returns TRUE...

=ISNUMBER(--(YEAR(A1)&"-02-29"))

Rick

"Rick Rothstein (MVP - VB)" wrote in
. ..



Actually, I take that back... at one function call less, I think this one
is more efficient...

=365+ISNUMBER(--(YEAR(TODAY())&"-02-29"))

Rick

"Rick Rothstein (MVP - VB)" wrote in
l...
But won't something like:

=365+(MONTH(DATE(YEAR(TODAY()),2,28)+1)=2)

do just as well?

I came up with a similar idea, just expressed differently...

=365+ISNUMBER(MONTH(--(YEAR(TODAY())&"-02-29")))

Same number of function calls, but yours avoids the concatenation, so I'm
guessing yours is more efficient.

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