Perhaps Joel intended to use MOD(...,1), rather than INT(...) ?
--
David Biddulph

"Sandy Mann" wrote in message
...
"Joel" wrote in message
...


The Int() rounds the time value to remove the date.


Are you sure? Times are a fraction so the INT() is removing the fraction,
(ie time), not the whole number (ie Date)
--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


Replace @mailinator.com with @tiscali.co.uk


"Joel" wrote in message
...
use the Hour function

Mytime = TimeValue("09/01/2008 16:53")
If (Hour(Mytime) = 9) And (Hour(Mytime) <= 17) Then
a = 1
End If

or
=IF(AND(HOUR(B5)=9,HOUR(B5)<=17),"Yes","No")

these solutions don't include exactly 5:00 PM

Another solution

Mytime = TimeValue("09/01/2008 16:53")
If (Int(Mytime) = timevalue("9:00 AM")) And (Int(Mytime) <=
timevalue(5:00
PM")) Then

End If

=IF(AND(int(B5)=timevalue("9:00 AM"),Int(B5)<=timevalue("5:00
PM")),"Yes","No")


The Int() rounds the time value to remove the date.
"Dom" wrote:

Hi I have been working on some information that shows when a job was
logged
and when it was then completed. I have times for these both and have
been
able to work out the difference between these dates in workdays and
figure
out the times ( dd:hh:mm) but I now need an if statement for if the time
to
only count hours after 9am and before 5pm. For example I want to work
out 32
working hours from
09/01/2008 06:53
I have worked out the working days so I currently have
10/01/2008 14:53
but I only want it to work out the 32 hours from 09:00 - 17:00 every
day
Is there any way of doing this?