Just the same as befo

=IF(J26=0,0,(E34+H34)/J26)

or:

=IF(OR(J26=0,J26=""),"",(E34+H34)/J26)

depending of what may be in J26. If only ever a BLANK cell or a number then
the first one. If J26 *may* contain an empty string, (for instance if J26
had a forrmula like: =IF(J16="","",10) which will return "" or 10) then use
the second one.

--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


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"Peter" wrote in message
...
I have the formula
=(e34+h34)/j26
it gives me the #div0! error.
I want it to read 0

"Sandy Mann" wrote:

I don't understand what you mean by:

reads =(e34+h34)/j26. How do I get the ) in that formula?

) ??


--
Regards

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


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"Peter" wrote in message
...
That worked thanks, it helped alot. However what if I have a formula
that
reads =(e34+h34)/j26. How do I get the ) in that formula?

"Sandy Mann" wrote:

Try:

=IF(G3=0,0,AM3/G3)

Note: no need for the SUM() function.

or:

=IF(G3=0,"",AM3/G3)

To return an empty looking cell instead of a zero.

If there is any chance that G3 may contain an empty string, (from a
formula)
then use:

=IF(OR(G3=0,G3=""),"",AM3/G3)

HTH

Sandy

In Perth, the ancient capital of Scotland
and the crowning place of kings


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"Peter" wrote in message
...
I have this formula =SUM(AM3/G3) I need the cell to read zero, right
now
it
gives me a #div!