I inserted =OR(R23<=14,ERROR.TYPE(4)) but it didn't work.

.TYPE(4)) What is this part of the formula for?

Ken


"Kevin B" wrote:

Try changing your first criteria to the following:

=OR(R23<=14,ERROR.TYPE(4))

I think that will do it for you.
--
Kevin Backmann


"Ken" wrote:

I'm using 3 conditions for cell J7 which are as follows:

=AND(R23<=14) Green
=AND(R2314,R23<=30) Yellow
=AND(R2330) Red

This works fine if there are no errors in cell R23. If there is an error in
cell R23 the cell turns red. (Error being #REF!)


My question is this ...

Is there a way to turn cell J7 green if cell R23 displays #REF! ?

There are times when cell R23 displays #REF! due to the fact that the pivot
didn't have data to return. The formula I have in cell R23 is as follows:

=IF(ISERROR(GETPIVOTDATA("Max Open Age",'Pivot1(Total
Ticket)'!$A$3,"REGION_ROLLUP","CALA")),"0.0",GETPI VOTDATA("Max Open
Age",'Pivot1(Total Ticket)'!$A$3,"REGION_ROLLUP","CALA"))

Using the above error formula does populate cell R23 with 0.0 but I can't
get the conditional formatting in J7 to recognize it.

Can anyone help?