I ***think*** this array-entered formula might work...

=AND(AND(MID(A1,ROW($1:$5),1)="A",MID(A1,ROW($1:$ 5),1)<="Z"),AND(MID(A1,ROW($6:$9),1)="0",MID(A1,R OW($6:$9),1)<="9"),AND(MID(A1,10,1)="A",MID(A1,10 ,1)<="Z"),LEN(A1)=10)

Note for the archives: Commit this formula with Ctrl+Shift+Enter instead of
just Enter by itself.

Rick


"T. Valko" wrote in message
...
Still chokes:

?A?c*0000?
*****1234*
**a??0000x


--
Biff
Microsoft Excel MVP


"Bob Phillips" wrote in message
...
=AND(LEN(A1)=10,SUM(--(NOT(ISNUMBER(MATCH(UPPER(MID(A1,ROW($1:$5),1)),CH AR(ROW(INDIRECT("65:90"))),0)))))=0,
SUMPRODUCT(--(ISNUMBER(--MID(A1,ROW(INDIRECT("6:9")),1))))=4,ISNUMBER(MATCH (UPPER(RIGHT(A1,1)),CHAR(ROW(INDIRECT("65:90"))),0 )))

there you go.

--
---
HTH

Bob


(there's no email, no snail mail, but somewhere should be gmail in my
addy)



"Rick Rothstein (MVP - VB)" wrote
in message ...
You will need to add something for the length... ABCDE1234FABCDEF
evaluates to TRUE.

Rick


"Bob Phillips" wrote in message
...
=AND(SUM(--(NOT(ISNUMBER(MATCH(UPPER(MID(A1,ROW($1:$5),1)),CH AR(ROW(INDIRECT("65:90"))),0)))))=0,SUMPRODUCT(--(ISNUMBER(--MID(A1,ROW(INDIRECT("6:9")),1))))=4,ISNUMBER(MATCH (UPPER(RIGHT(A1,1)),CHAR(ROW(INDIRECT("65:90"))),0 )))

an array formula.

Before anyone pulls me up about ROW($1:$5) (as if!), I included it as
ROE(INDIRECT exceeds 7 nested functions.

--
---
HTH

Bob


(there's no email, no snail mail, but somewhere should be gmail in my
addy)



"Rick Rothstein (MVP - VB)" wrote
in message ...
I'm beginning to think the only "foolproof" way to do this might be
this formula...

=AND(MID(A1,1,1)="A",MID(A1,1,1)<="Z")+AND(MID(A1 ,2,1)="A",MID(A1,2,1)<="Z")+AND(MID(A1,3,1)="A", MID(A1,3,1)<="Z")+AND(MID(A1,4,1)="A",MID(A1,4,1) <="Z")+AND(MID(A1,5,1)="A",MID(A1,5,1)<="Z")+AND( MID(A1,6,1)="0",MID(A1,6,1)<="9")+AND(MID(A1,7,1) ="0",MID(A1,7,1)<="9")+AND(MID(A1,8,1)="0",MID(A 1,8,1)<="9")+AND(MID(A1,9,1)="0",MID(A1,9,1)<="9" )+AND(MID(A1,10,1)="A",MID(A1,10,1)<="Z")=10

although I do note some ALT+0### "type-able" keyboard characters (for
example, ALT+0140, ALT+0153, and others) will pass the test; however,
it would be foolproof for the "normal" keyboard characters.

Rick


"Rick Rothstein (MVP - VB)"
wrote in message ...
I'm sorry, but it turns out there is still a problem... none of the
"letter" entry characters need to actually be letters to pass through
your formula. Here is one of the several worst possibilities that
your formula will return TRUE for...

$+#%&1234*

Rick


"Bob Phillips" wrote in message
...
easily resolved

=AND(SUMPRODUCT(--(ISNUMBER(--MID(A21,ROW(INDIRECT("1:5")),1))))=0,SUMPRODUCT(--(ISNUMBER(--MID(A21,ROW(INDIRECT("6:9")),1))))=4,NOT(ISNUMBER(--RIGHT(A21,1))))

--
---
HTH

Bob


(there's no email, no snail mail, but somewhere should be gmail in
my addy)



"Rick Rothstein (MVP - VB)"
wrote in message ...
That formula is not foolproof; for example, consider these
entries...

ABCDE12.3F
ABCDE+123F
ABCDE$123F
ABCDE(12)F

Rick


"Bob Phillips" wrote in message
...
=AND(SUMPRODUCT(--(ISNUMBER(--MID(A21,ROW(INDIRECT("1:5")),1))))=0,ISNUMBER(--MID(A21,6,4)),NOT(ISNUMBER(--RIGHT(A21,1))))

--
---
HTH

Bob


(there's no email, no snail mail, but somewhere should be gmail in
my addy)



"Sai Krishna" wrote in
message ...
Hi,

I have a cell where in I need to enter an alphanumeric strictly
as under

AAAAI7504G

The rule is : First 5 should be alphabets, next 4 should be
numbers and the
last again an alphabet.

The total characters are therefore 10. For the length of the
character, we
can use Text length under Data validation. But we need to ensure
that rule is
followed.

The above is only an illustration. But the positions of alphabets
and
numbers should be as per the rule above.

Now is there any formula that throws up a warning saying that a
number has
been entered in place of an alphabet. In other words, the above
rule should
not be violated.

regards
krishna