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covingj covingj is offline
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Default find value on table and print column lable

Thank you, that appears to work very well. Now to try to understand it and
apply.

"Ron Coderre" wrote:

With your posted data in A1:E5

And
G1: (an income....eg $1800)
H1: (a family size...eg 3)

This formula return the associated percentage from Row_1:
=INDEX(B1:E1,MATCH(1,FREQUENCY(G1,OFFSET(B1:E1,H1, ,)),0))

In the above example, the formula returns 125%

Is that something you can work with?
--------------------------

Regards,

Ron
Microsoft MVP (Excel)
(XL2003, Win XP)
"covingj" wrote in message
...
I want to create a table with income figures and then look up values based
on
household size that is calculated and then return the column lable. For
instance, a 4x4 table with family size 1, 2, 3, 4 and column lables of
100%,
125%, 150% and 175%. The grid is filled with income amounts at each
intersection.

100% 125% 150% 175%
1 500 625 750 875
2 1000 1250 1500 1750
3 1500 1875 2250 2625
4 2000 2500 3000 3500

I want to look up an income amount for a calculated household size (using
a
count function), and return the column lable to show the percentage, so
that
a household of three with income of $1800 will return a value of 125%