I thought so at first, but it's not exactly what I'm looking for. It is very
close and perhaps the best I could expect. the perfect solution would treat
..10 as .20, so you would never have an odd number .30, .50,.70,.90. For
expmple between 1 & 2 you would have only .20,.40,.60,.80 then 2.0, counting
by fifths.

Perhaps it's not possible?

M.A.

"MartinW" wrote:

Hi MA,

Sorry for the confusion, but doesn't Chip Pearson's reply
about DOLLARDE and DOLLARFR solve your problem?

HTH
Martin


"M.A.Tyler" <Great Lakes State wrote in message
...
Yes!, can you help?

"Bob I" wrote:

Umm, fifths would be .0, .2, .4, .6, and .8 so what is it you really
want? .5 is equal to 2 and 1/2 "fifths" not one.

M.A.Tyler wrote:

Sorry, I would like a method to calculate simple mathmatical problems
using
the decimal portion as fifths rather than tenths. in other words .50
would
equal 1 not 1/2.

Sorry for the confusion.

"MartinW" wrote:


Hi M.A.

Your question is rather unclear,

=24.5-24.2 = 0.3 (yes that's right)

=20.4+0.1 = 20.5
=round(20.4+0.1,0) = 21

What are the fifths that you are talking about?

Regards
Martin


"M.A.Tyler" <Great Lakes State wrote in message
...

Is it possible to perform simple addition and subtraction in fifths?
something like 24.5 - 24.2=.3,
or
20.4 + 0.1=21

Thanks.

M.A.Tyler