countif
Nope.
But you could use:
=sumproduct(--(isnumber(search("cabg",b1:b5))), ...
or
=sumproduct(--(isnumber(search(a1,b1:b5))), ...
=Search() is not case sensitive.
=Find() is case sensitive.
JRD wrote:
Does this formula still hold true if one is using sumproduct e.g.
e.g.
A B C
1 CABG CABG Yes
2 CABG No
3 PCI No
4 CABG, PCI Yes
5 PCI Yes
So if I want to count the number of rows in which both Column B contains
CABG and column C contains yes, which of the following formulae will give me
the right answer of 2
=SUMPRODUCT(--(B1:B5=A1), --(C1:C5="Yes"))
OR
=SUMPRODUCT(--(B1:B5="*" & A1 & "*"), --(C1:C5="Yes"))
Additionally what formula would I use if I wanted to know the number of rows
in which both Column B contains exactly CABG and column C contains yes i.e.
the answer would be 1
Thanks
John
"Dave Peterson" wrote:
=countif(b1:b5, "*" & a1 & "*")
JRD wrote:
Is there a way of counting the number of cells in a column that contain at
least in part a certain string variable that is contained in another cell
using for instance the countif function
e.g.
A B
1 CABG CABG
2 CABG
3 PCI
4 CABG, PCI
5 PCI
=countif(b1:b5, a1)
I want the answer to be 3, but the above function gives an answer of 2
because cell B4 does not fit exactly. However, I do want to use a1 as the
criteria and not just put "*CABG*" instead
--
Dave Peterson
--
Dave Peterson
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