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RagDyeR RagDyeR is offline
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Default Help in finding Value in Index Array

Appreciate the feed-back ...*BUT* ...
If there's *any possibility* that you might have zeroes in Column C,
Make sure that you use either my *revised* formula, or Peo's formula.

Peo's formula *does* work!
Don't know what you might have done, that you had trouble trying it out.

As far as I can tell, *both* formulas do *exactly* the same thing!
--
Regards,

RD

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"George" wrote in message
...
That works!

Thank you both very much.

"RagDyer" wrote:

Works OK for me!
--
Regards,

RD

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"Peo Sjoblom" wrote in message
...
That formula does not work for me,it fails if G5 is zero


--


Regards,


Peo Sjoblom




"RagDyer" wrote in message
...
Try this *array* formula:

=INDEX(INDEX(G5:G40,MATCH(TRUE,C5:C40=0,0)):G40,
MATCH(TRUE,INDEX(G5:G40,MATCH(TRUE,C5:C40=0,0)):G4 00,0))

--
Array formulas must be entered with CSE, <Ctrl <Shift <Enter,
instead
of
the regular <Enter, which will *automatically* enclose the formula in
curly
brackets, which *cannot* be done manually. Also, you must use CSE
when
revising the formula.

--
HTH,

RD

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"George" wrote in message
...
It now shows #N/A. Could it be because Column G has blank (empty
cell)
rows
before the first positive value?

"Peo Sjoblom" wrote:

Try this

=INDEX(G5:G400,MATCH(TRUE,INDEX(INDEX(G5:G400,MATC H(TRUE,C5:C400="",0)):G400,0)0,0)+MATCH(TRUE,C5:C 400="",0)-1)

array entered


--


Regards,


Peo Sjoblom



"George" wrote in message
...
I am looking for the first positive value in column G (not C),
after
the
first empty cell in column C.

(I tried just replacing the C & G's but it didn't work.)

"Peo Sjoblom" wrote:

Either I totally misunderstood what you wanted or you are not
using
the
same
cell references/formula as posted because it does return the
first
value
in
C5:C400 greater than zero starting from the first blank cell in
G5:G500.
This is what I have starting in G5

0
8
7
6
5
4
3
2
1
0
-1
-2
-3
-4
-5
-6
-7

8

9


so the first blank is below -7 in C22, this is what I have
starting
in C5

0
-17
-16
-15
1
-13
-12
16
-10
-9
-8
-7
-6
-5
-4
-3
-2
-1
0
0
0
0
0
5
6
7
8
9
10


the first value greater than 0 starting in row C22 is 5 in cell
C28
and
that is what my formula returns


--


Regards,


Peo Sjoblom




"George" wrote in message
...
Hi Peo,
Sorry but that returns the C5 value (column G is zero at that
point, if
it
helps). I need the first positive number in column G after
column
C is
empty.

Thanks,


"Peo Sjoblom" wrote:

I misunderstood, I thought you were looking for zero in column
G,
this
will
work

=INDEX(C5:C400,MATCH(TRUE,INDEX(INDEX(C5:C400,MATC H(TRUE,G5:G400="",0)):C400,0)0,0)+MATCH(TRUE,G5:G 400="",0)-1)



--


Regards,


Peo Sjoblom



"George" wrote in message
...
Hi Peo,
Thanks, but the formula below returns the first value in
column
C
(after
row
5), but I am actually looking for the first positive value
in
column
G
after
column C declines to an empty cell.



"Peo Sjoblom" wrote:

One way

=INDEX(C5:C400,MATCH(TRUE,INDEX(INDEX(C5:C400,MATC H(1,(G5:G400=0)*(G5:G400<""),0)):C400,0)0,0)+MAT CH(1,(G5:G400=0)*(G5:G400<""),0)-1)

entered with ctrl + shift & enter


--


Regards,


Peo Sjoblom



"George" wrote in
message
...
I am trying to search a column (C5:C400) to find out when
it
runs
to
a
null
value, then search down a different column (G) starting
from
that
same
row
and return the first positive number found.

Can anyone help? I've been using the following as a
starting
point,
but
I'm
stuck on how to complete it.

=INDEX(MATCH(TRUE,G5:G4000),MATCH(TRUE,C5:C400=0, 0))

Thanks!