View Single Post
  #9   Report Post  
Posted to microsoft.public.excel.misc
Farhad Farhad is offline
external usenet poster
 
Posts: 281
Default Dragging a formula with cell references

Welcome! but the important point was 64+COLUMN()*3 which Don Guillett solved
it. Thank you Don for your solution!

Thanks,
--
Farhad Hodjat


"Sasikiran" wrote:

Thanks a ton Farhad... its working fine now..

"Farhad" wrote:

Hi,

The formula that i correct for you works just to column Z and if you have
more column so you have to expand the formula as below:

=INDIRECT(IF(64+COLUMN()*390,IF(64+COLUMN()*3-2690,"'Sheet2'!B"&CHAR(64+COLUMN()*3-52),"'Sheet2'!A"&CHAR(64+COLUMN()*3-26)),"'Sheet2'!"&CHAR(64+COLUMN()*3))&34)

so this formula works till column BZ

Thanks,
--
Farhad Hodjat


"Sasikiran" wrote:

Hi Farhad,

Can you please help me more on this?

The data has to be copied thru a formula from a different sheet (sheet2) to
sheet 1.

The formula in A1 of sheet 1 is ='Sheet2'!C34
The formula in B1 of sheet 1 is ='Sheet2'!F34
The formula in C1 of sheet 1 is ='Sheet2'!I34

How do I incorporate in this formula

=INDIRECT(CHAR(COLUMN()*3+64)&34)

Im trying in this way..

=INDIRECT(CHAR('Sheet2'!C34*3+64)&34)

Please trying all the possible ways... please tell me where i'm going wrong

Thanks in advance
Sasikiran




"Farhad" wrote:

Hi,

a small correction:

=INDIRECT(CHAR(COLUMN()*3+64)&34)

enter this formula in the cell A1 and then copy drag it to B, C, D, .....


Hello,

I have a problem while dragging the formula to the next cells.

The formula in A1 of sheet 1 is ='Sheet2'!C34
The formula in B1 of sheet 1 is ='Sheet2'!F34
The formula in C1 of sheet 1 is ='Sheet2'!I34

Here while dragging the formula, the next cell has to take the value of
the
same row (34) of every third column C, F, I, L... so on. But while
dragging
its not coming the same way.

Can anyone suggest me how to do that?

Thanks in advance
Sasikiran