find % number from text string
The following UDF will display the percent value as a string:
Function percentality(s As String) As String
parts = Split(s, "%")
MsgBox (parts(0))
t = Right(parts(0), 2)
MsgBox (t)
If IsNumeric(t) Then
percentality = t & "%"
Exit Function
End If
t = Right(parts(0), 1)
If IsNumeric(t) Then
percentality = t & "%"
Exit Function
End If
percentality = ""
End Function
so if A1 contains:
there is 12% by volume
then
=percentality(A1) will display:
12%
as text
--
Gary''s Student - gsnu2007
"natek1234" wrote:
I am trying to come up with a formula to display a percentage in
another cell from a long string of other random text and if none to
show up at 0%. For example, the string in C1 is "(10%, 1, 15hr) blah
blah blah" i need a cell that finds the 10 and displays 10% and if
there is no % to display 0%. can anyone help me?
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