vba outcome
several things
where is length defined?
I would do it as
for i = 2 to length
(by going from 1 to length you have the j going from one to zero the first
iteration, whch it wont do
If A(j) < A )j +1) Then
needs to be
If A(j) < A (j +1) Then
x = a(j +1) = A(j)
needs to be
x=A(j+1)
A(J+1)=A(J)
"harry buggy" wrote:
can anyone tell me if theres any errors in this and what the outcome
would be?
sub test ()
dim I, J As Integer
dim x as single
for i = 1 to length
for j = 1 to (length - i)
If A(j) < A )j +1) Then
x = a(j +1) = A(j)
A(j) = x
end if
next j
next i
end sub
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