"if formula"
The answer to your question is actually quite easy, except that your info is
rather confusing. I take it you are getting all these variables from cell
addresses though.
Lets say Variable hours is in col A; variable % in Col B and Standard
133.3333% in C1, then
=IF(A5<=37.5,A5*3.37*B5*$C$1,168.5*B5*$C$1)
In row 6 this will change to
=IF(A6<=37.5,A6*B6*$C$1,168.5*B6*$C$1)
--
Hth
Kassie Kasselman
Change xxx to hotmail
"Shaz" wrote:
Ok, get ready for a long winded post, as it is confusing....
Basically, the a couple of parts that I need to the formula, not sure if it
will be possible though....
Here is the BASIC formula that I need to work from:
Variable Hours * 3.37 * variable % * (either 85% or 100%) * standard
133.3333% =
Now, IF the variable HOURS are greater than 37.5, then the formula changes
to the following.....instead of multiplying 3.37 by the hours, there is a
standard fee of 168.50
So, this formula would be something like this:
if variable hours 37.5 = 168.50 * variable % * (either 85% or 100%) =
It is all very complicated......but it is a formula that needs to be used in
order to work out charge out fees, and as you can see, it would be much
easier if all I have to do is put in the variable hours and then point to the
clients variable % (which is a different % for each client, but the same once
allocated) and also point to the 85% or 100% depending on which one they are
charged.....
I know this is all sounding very complicated, which is why I desperately
need help....any formula whizzes out there would be greatly appreciated and
more than likely a great challenge!!!!
If you need me to further elaborate, please advise, as I have tried my best
to explain it as simply as possible.....
Shaz
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