Too many nested IF functions!
Thanks everyone for your assistance in answering this question for me. I
apologize for not being more clear in my description of the situation. The
numbers 1-9 (another error I made in my problem description was that I wrote
0 through 9!) are entered manually in a random order, but all 9 numbers must
be represented.
The solution which Biff provided below resolved my situation completely!!!
THANKS SO MUCH!!
"T. Valko" wrote:
Try this:
=INDEX(C4:K4,MATCH(TRUE,INDEX(COUNTIF(C4:K4,C4:K4) 1,1,),0))
If more than one number is duplicated the formula will return the *first*
matched duplicate.
--
Biff
Microsoft Excel MVP
"Skyscan" wrote in message
...
I am trying to determine if a data array has duplicate numbers. The
numbers
in C4:K4 are randomly 0 through 9, however sometimes an error occurs and a
duplicate number is inserted into the array. If a duplicate number is
entered, I want the duplicate number to show up in the cell. I am running
up
against the max limit of 7 nested IF() functions. The function string
below
works, however I need to check for duplicate 8's and 9's. How can I get
around this nested IF limit?
=IF(COUNTIF(C4:K4,"1")1,"1",IF(COUNTIF(C4:K4,"2") 1,"2",IF(COUNTIF(C4:K4,"3")1,"3",IF(COUNTIF(C4:K 4,"4")1,"4",IF(COUNTIF(C4:K4,"5")1,"5",IF(COUNTI F(C4:K4,"6")1,"6",IF(COUNTIF(C4:K4,"7")1,"7","") ))))))
Thank you in advance!!!
Tom
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