Roger's formula works great. Except you will need to change the 'min' range
from 'B2:B2' to 'B2:D2'
--
T Tipsy


" wrote:

This is my data:

ST AFNW LNHM RJWL BEST CARRIER
DE $1.35 $1.51 $1.35 AFNW
FL $1.75 $1.90 $1.30 $1.30 #N/A
GA $1.75 $1.34 $1.25 $1.25 #N/A
IA $1.20 $1.17 $1.25 $1.17 LNHM
ID $2.25 $2.15 $2.15 LNHM
IL $1.20 $1.35 $1.25 $1.20 AFNW

I'm attempting to return a value in the heading row (AFNW, LNHM, RJWL) as
the result of the CARRIER column, when the value in the BEST column in found.


So basically I'm identifying the lowest rate and the name of the Carrier
that has that low rate.

Rows 2, 5-7 are working correctly. Rows 3 and 4 are not. The result of the
BEST column (Column E) is found by returning the MIN value in columns B-D. It
seems that whenever the MIN value is equal to the RJWL column (Column D), a
value of #N/A is returned in the CARRIER COLUMN.

These are the two formulas I'm using:

=MIN(B2:D2) is the formula for BEST COLUMN (Column E)
=LOOKUP(E2,B2:D2,$B$1:$D$1) is the formula for CARRIER COLUMN

Please help.