Hi Rick and Peo
Firstly apologies to the OP, I should have changed the double unaries to
asterisk, not just copied his formula and placed the array around the
two cities.
Peo, the arrays are of the same size, although one of them could have
two outcomes True or False.
These are mutually exclusive however for each cell within the range.
When you use the double unary minus, however, each True or False is
converted instantly into a 1 or 0, so you do end up with a problem.
When you use the asterisk, the coercion to 1's and 0's doesn't take
place until both sets of criteria have been evaluated
Consider the following small example
=SUMPRODUCT(($C$2:C$4={"Ottawa","Toronto"})*($D$2: $D$4="Ontario"))
With C2=Ottawa, C3 =blank and C4 =Toronto
With D2=Ontario, D3 =blank and D4 =Toronto
The result from the first test is
True, False; False, False; False, True
and from the second it is
True; False; True
Note the semicolons as compared with the commas.
Now, when these two arrays are multiplied together with the asterisk,,
only then do we get
1, 0; 0, 0; 0, 1
which sums to 2
With the double unary, the first set of True/False's are changed to
{1, 0; 0, 0; 0, 1}
whilst the second term is still --{True;False;True}
so for the next part of the evaluation, Sumproduct does object because
there are twice as many values in the first term as in the second.
So, I believe it is all due to the order of coercion.
--
Regards
Roger Govier
"Ragdyer" wrote in message
...
But Peo, that's not telling me why the asterisk form *does* work!
--
Regards,
RD
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"Peo Sjoblom" wrote in message
...
It's because this part
Calculations!$M$2:M$3959={"Ottawa","Toronto"}
will create twice as many TRUE or FALSE
as this
Calculations!$I$2:I$3959="Ontario"
and you cannot use the built in way of SUMPRODUCT with that, try
=SUMPRODUCT(A1:A10,B1:B5)
and it will return a value error
AFAIK you can only use it like
=SUMPRODUCT(--((Calculations!$M$2:M$3959="Ottawa")+(Calculations !$M$2:M$3959="Toronto")0),--(Calculations!$I$2:I$3959="Ontario"))
--
Regards,
Peo Sjoblom
"RagDyeR" wrote in message
...
I'm getting the same #Value! error, and I don't understand it.
I *don't* know why, but this is working, while the other is not!
=SUMPRODUCT((Calculations!$M$2:M$3935={"Ottawa","T oronto"})*(Calculations!$I$2:I$3935="Ontario"))
--
Regards,
RD
-----------------------------------------------------------------------------------------------
Please keep all correspondence within the Group, so all may benefit
!
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"srain001" wrote in message
...
Hi,
Unfortunately, this isn't working. I get a result of #VALUE in the
cell.
I'm referencing the right columns and the spelling is correct, so
I'm
baffled...
Any other ideas?
Thanx
S.
"Roger Govier" wrote:
Hi
Create an array of Ottawa and Toronto, which is saying either
Ottawa OR
Toronto.
=SUMPRODUCT(--(Calculations!$M$2:M$3935={"Ottawa","Toronto"}),
--(Calculations!$I$2:I$3935="Ontario"))
--
Regards
Roger Govier
"srain001" wrote in message
...
Hello,
I am looking for a way to capture info from one column while
referring
it to
another. For example, the info I'm analyzing pertains to cities
and
the
provinces in which they're located. I'd like to find a way in
which I
can
capture instances in which multiple cells in Column A refer to
one
cell in
Column B. (i.e. Ottawa and Toronto are both located in Ontario)
I've
tried
a SUMPRODUCT formula, but it won't let me put multiple instances
in
the same
calculation. Is there something else I can try?
This is what I'm currently trying, but unable to make work:
=SUMPRODUCT(--(Calculations!$M$2:M$3935="Ottawa","Toronto"),--(Calculations!$I$2:I$3935="Ontario"))
When I try it with simply "Ottawa" it works, but when I try to
add
another
city, an error appears.
This is an example of the data I have:
Column A
Hafford
Ottawa
Toronto
Montreal
Column B
Saskatchewan
Ontario
Quebec
Thanx!
Srain