Are you changing those values -- or are they the results of a formula?
If you're changing them yourself, you could use a worksheet_change event.
If you want to try this, rightclick on the worksheet tab that should have this
behavior. Select view code and paste this into the code window:
Option Explicit
Private Sub Worksheet_Change(ByVal Target As Range)
Dim myRng As Range
Dim myCell As Range
Set myRng = Intersect(Target, Me.Range("a:a"))
If myRng Is Nothing Then
Exit Sub
End If
For Each myCell In myRng.Cells
If IsNumeric(myCell.Value) Then
If Int(myCell.Value) = myCell.Value Then
myCell.NumberFormat = "General"
Else
myCell.NumberFormat = "#,##0.0000"
End If
End If
Next myCell
End Sub
I only changed the format in column A.
Did you really mean this: #,##0.####?
Roee wrote:
OK, since that is what Sandy suggested I guess this is as close as it gets.
Any chance that conditional formatting or some VB function can solve it?
Something in general tenor of:
if the number is an integer show in "General" formatting
else use #,##0.####
Roee.
"Bob Phillips" wrote:
The you need
#,##0.####
but you will always see the dot.
--
---
HTH
Bob
(there's no email, no snail mail, but somewhere should be gmail in my addy)
"Roee" wrote in message
...
But I want it to show decimal parts *if they exists*.
I want to see 1000.05 as 1,000.05 (and not 1,000 or 1000.05) and 1,000 as
1,000 (and not 1,000.00).
Using a fixed 0 decimal places or a format of #,##0 does not allow it.
Any suggestions?
Thanks,
Roee.
"Bob Phillips" wrote:
Use a format of #,##0.
--
---
HTH
Bob
(there's no email, no snail mail, but somewhere should be gmail in my
addy)
"Roee" wrote in message
...
Hello,
I would like to use the 1000 sperator but I don't want to specify fixed
decimal places.
For example, if the cell contains the number 300, I want it to show 300
and
not 300.00, but I still wan't to use the 1000 sperator.
How do I do that?
The "General" formatting showes the decimal places like I want (only if
exists) but does not allow 1000 sperator and the "Number" formatting
requires
defining a fixed number of decimal places.
Thanks,
Roee.
--
Dave Peterson