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sumproduct mod row
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denise
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sumproduct mod row
Hi Sandy,
Thanks for your suggestion. I do get False for some of the cells that should
be numbers. I set the format to number and still get False. These number
cells are actually formulas to pull the number results from a different
sheet: ='1'!T22
Denise
"Sandy Mann" wrote:
Try working out which cell one of the #VALUE! returns is being returned
from - say it was A65 - then try in an empty cell the formula:
=ISNUMBER(A56)
If you do not get TRUE then the entry is text even if it looks like a number
--
HTH
Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings
with @tiscali.co.uk
"denise" wrote in message
...
There aren't any visible #VALUE! errors in the range however when I
evaluate
the formula, I see #VALUE! in most of the cells. The way the spreadsheet
is
set up every other line is text:
row 16 Concession
row 17 1
row 18 Affidavit
row 19 0
row 20 AWAS
row 21 0
etc., with the items repeating every 13th row (rows 15-27 are for Day 1,
rows 28-40 for Day 2...)
Could the text be causing the #VALUE! error?
Thanks,
Denise
"JE McGimpsey" wrote:
It works fine for me. Do you have any #VALUE! errors in O17:O407??
However, if you want to start with the value in row 17, use
(MOD(ROW(17:407),13)=4)
instead.
In article ,
denise wrote:
Hello folks,
I'm hoping someone can help me since I have hit a snag in trying to
modify a
formula.
This formula is working now (in J3) to sum starting with the value in
row 11
and then adding every 7th row:
=SUMPRODUCT((J11:J221)*(MOD(ROW(11:221),7)=4))
I want to adapt this (in O4) to sum starting with the value in row 17
and
then add every 13th row. I've tried
=SUMPRODUCT((O17:O407)*(MOD(ROW(17:407),13)=3)) but I get #VALUE. I'm
guessing the problem is with the =3 at the end of the formula but I
can't
figure out what it should be. Any ideas?
Thanks,
Denise
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